4cos^4(2x)+4sin(2x)=5

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Solution for 4cos^4(2x)+4sin(2x)=5 equation:


Simplifying
4cos4(2x) + 4sin(2x) = 5

Remove parenthesis around (2x)
4cos4 * 2x + 4sin(2x) = 5

Reorder the terms for easier multiplication:
4 * 2cos4 * x + 4sin(2x) = 5

Multiply 4 * 2
8cos4 * x + 4sin(2x) = 5

Multiply cos4 * x
8cos4x + 4sin(2x) = 5

Remove parenthesis around (2x)
8cos4x + 4ins * 2x = 5

Reorder the terms for easier multiplication:
8cos4x + 4 * 2ins * x = 5

Multiply 4 * 2
8cos4x + 8ins * x = 5

Multiply ins * x
8cos4x + 8insx = 5

Solving
8cos4x + 8insx = 5

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8insx' to each side of the equation.
8cos4x + 8insx + -8insx = 5 + -8insx

Combine like terms: 8insx + -8insx = 0
8cos4x + 0 = 5 + -8insx
8cos4x = 5 + -8insx

Divide each side by '8os4x'.
c = 0.625o-1s-4x-1 + -1ino-1s-3

Simplifying
c = 0.625o-1s-4x-1 + -1ino-1s-3

Reorder the terms:
c = -1ino-1s-3 + 0.625o-1s-4x-1

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